PROBLEM: ajackson@keck.tamu.edu (Andrew J. Jackson)
　　
　　I'm inquiring on how to declare a reference to an array of integers
　　
　　
　　RESPONS: Efim Birger (efim@microware.com)
　　
　　try this:
　　
　　typedef int *intp;
　　int arr[10];
　　intp& aaa = arr;
　　
　　
　　RESPONSE: fjh@munta.cs.mu.OZ.AU (Fergus Henderson), 11 Aug 94
　　
　　This code is illegal. `aaa' is a (non-const) reference to a pointer to int.
　　`arr' is an array of int, which will be converted to a pointer to int.
　　The result of that conversion is a temporary.
　　You are initializing a non-const reference with a temporary, which is illegal.
　　
　　
　　RESPONSE: admin@rzaix13.uni-hamburg.de (Bernd Eggink)
　　
　　There is no sUCh thing as a reference to an array.
　　
　　
　　RESPONSE: fjh@munta.cs.mu.OZ.AU (Fergus Henderson)
　　
　　There most certainly is.
　　(An array of references is illegal, but a reference to an array is quite OK.)