1254 active_tasks = count_active_tasks();
1256 CALC_LOAD(avenrun[0], EXP_1, active_tasks);
1257 CALC_LOAD(avenrun[1], EXP_5, active_tasks);
1258 CALC_LOAD(avenrun[2], EXP_15, active_tasks);
//include/linux/sched.h
110 #define FSHIFT 11 /* nr of bits of precision */
111 #define FIXED_1 (1 112 #define LOAD_FREQ (5*HZ) /* 5 sec intervals */
113 #define EXP_1 1884 /* 1/exp(5sec/1min) as fixed-point */
114 #define EXP_5 2014 /* 1/exp(5sec/5min) */
115 #define EXP_15 2037 /* 1/exp(5sec/15min) */
117 #define CALC_LOAD(load,exp,n)
118 load *= exp;
119 load += n*(FIXED_1-exp);
120 load = FSHIFT;
load(t) = ( load(t-1)*exp(i) + n(t)*(2048-exp(i)) ) / 2048
load(t-1)为上次计算出的结果
n(t)为t时刻的活动进程数
计算方式是累加各个CPU的运行队列中running和uninterruptible的值 再乘以2048
计算方式如下:
1946 unsigned long nr_active(void) 1947 { 1948 unsigned long i, running = 0, uninterruptible = 0; 1949 1950 for_each_online_cpu(i) { 1951 running += cpu_rq(i)-nr_running; 1952 uninterruptible += cpu_rq(i)-nr_uninterruptible; 1953 } 1954 1955 if (unlikely((long)uninterruptible 0)) 1956 uninterruptible = 0; 1957 1958 return running + uninterruptible; 1959 }
(本文来源于图老师网站,更多请访问http://m.tulaoshi.com/diannaorumen/)1226 static unsigned long count_active_tasks(void) 1227 { 1228 return nr_active() * FIXED_1; 1229 }
exp(1) = 1884 exp(5) = 2014 exp(15) = 2037 exp(i) = 2048 * e^(-1/12/i)
从本质上看负载是完全由过去的一段时间里每个CPU上的活动进程数决定的,但并不是在数值上等同于每秒钟需要进行调度的进程数,具体的计算过程是个比较复杂的过程。